Talk:Integrator

Attention: Make sure the sum of your inputs does not exceed the machine unit (±10V), otherwise an overload will occur

I don't think this is correct. An overload occurs when the output exceeds the machine unit. However it should be no problem if the sum of the inputs exceeds the machine unit. — Preceding unsigned comment added by MKoch (talk • contribs)

Well, if the sum of the inputs exceeds the machine unit, the output will also do so, isn't it? You could think of cancellation of overloads (like in a sum with three inputs, two in overload but opposite sign, like +15V-15V+5V = +5V). This is a border case similar to saying +infinity - infinity + 5 = 5, because actually an overload value is typically an illegal value on the computer and the upcoming computation is most likely wrong. --Sven (talk) 13:51, 1 October 2021 (CEST)